Distance traveled at 55 mph with 5-second cushion

Distance traveled at 55 mph with 5-second cushion

• A. 400 ft
• B. 320 ft
• C. 420 ft
• D. 360 ft

Answer: (A)

The distance covered during a 5-second cushion is found by multiplying speed by time, using consistent units. Convert 55 mph to feet per second: 55 miles per hour equals 55 × 5280 feet per hour = 290,400 ft/hour, which is 290,400 ÷ 3600 ≈ 80.7 ft/s. In 5 seconds, that’s 80.7 × 5 ≈ 403.5 feet. The closest option is 400 feet. So the distance traveled is about 400 ft.

The distance covered during a 5-second cushion is found by multiplying speed by time, using consistent units. Convert 55 mph to feet per second: 55 miles per hour equals 55 × 5280 feet per hour = 290,400 ft/hour, which is 290,400 ÷ 3600 ≈ 80.7 ft/s. In 5 seconds, that’s 80.7 × 5 ≈ 403.5 feet. The closest option is 400 feet. So the distance traveled is about 400 ft.